d)  \(2x^2-3x-27\)

\(=\left(2x^2+6x\right)-\left(9x+27\right)\)

\(=2x\left(x+3\right)-9\left(x+3\right)\)

\(=\left(2x-9\right)\left(x+3\right)\)

e)  \(2x^2-5xy-3y^2\)

\(=\left(2x^2+xy\right)-\left(6xy+3y^2\right)\)

\(=2x\left(x+y\right)-3y\left(x+y\right)\)

\(=\left(2x-3y\right)\left(x+y\right)\)

a) 6x² - 11x + 3

= 6x² - 9x - 2x + 3

= 3x ( 2x - 3 ) - ( 2x - 3 )

= ( 2x - 3 ) ( 3x - 1 )

b ) 2x² + 3x - 27

= 2x² - 6x + 9x - 27

= 2x ( x - 3 ) + 9 ( x - 3 )

= ( x - 3 ) ( 2x + 9 )

c ) 2x² - 5xy - 3y²

= 2x² - 2xy - 3xy - 3y²

= 2x ( x - y ) - 3y ( x - y )

= ( x - y ) ( 2x - 3y )

Ta có: 

a) 6x² - 11x +3 = 2x(3x-1)-3(3x-1)=(2x-3)(3x-1)

b) 2x² +3x - 27= x(2x+9)-3(2x+9)=(x-3)(2x+9)

c) 2x²  -5xy-3y² = 2x(x-3y)+y(x-3y)=(2x+y)(x-3y)

a/ \(\left(x+3y\right)\left(2x-y\right)\)

b/ \(\left(x^2+2\right)\left(x^2-2\right)\left(x^2-2x+2\right)\left(x^2+2x+2\right)\)

b/ \(x^8-16=\left(x^4+4\right)\left(x^4-4\right)\)

\(=\left[\left(x^4+4x^2+4\right)-4x^2\right]\left(x^2-2\right)\left(x^2+2\right)\)

\(=\left[\left(x^2+2\right)^2-4x^2\right]\left(x^2-2\right)\left(x^2+2\right)\)

\(=\left(x^2+2+2x\right)\left(x^2+2-2x\right)\left(x^2-2\right)\left(x^2+2\right)\)

Ta có : 

2x^2-5xy-3y^2

 = 2^x + xy - 6xy - 3y^2  

= x(2x + y) - 3y(2x + y)  

= (2x + y)(x - 3y)

2x^2-5xy-3y^2

 = 2^x + xy - 6xy - 3y^2  

= x(2x + y) - 3y(2x + y)  

= (2x + y)(x - 3y)

Lời giải:

$A=x^2-8xy+15y^2=x^2-3xy-(5xy-15y^2)$

$=x(x-3y)-5y(x-3y)=(x-3y)(x-5y)$

$B=2x^2-5xy+2y^2=(2x^2-4xy)-(xy-2y^2)$

$=2x(x-2y)-y(x-2y)=(2x-y)(x-2y)$

$C=2x^2-3y^2-xy=(2x^2+2xy)-(3y^2+3xy)$

$=2x(x+y)-3y(y+x)=(x+y)(2x-3y)$

bài 1:

a) x(x-2)-5y-(x-2)=(x-5y)(x-2)

b) =(2x-3-4x)(2x-3+4x)=(-2x-3)(6x-3)

bài 2 bạn tự luyện nhé

a, 5x^2 +5xy - x - y 

= 5x ( x+ y ) - (x + y)

= ( 5x - 1)(x + y)

b, 2x^2  + 3x - 5 

= 2x^2 - 2x + 5x - 5 

= 2x( x - 1) + 5( x - 1)

= ( 2x + 5 )(x- 1 )

c; 16x - 5x^2 - 3 

c, = - ( 5x^2 - 16x + 3 )

   = - ( 5x^2 - x - 15x + 3 )

= - [ x(5x - 1 ) - 3 (5x - 1) ]

= - ( x- 3)(5x -  1 )

a) 5x² - 5xy - 3x + 3y

= 5x.(x - y) - 3.(x - y)

= (x - y).(5x - 3)

b) x³ - 2x² - x + 2

= x².(x - 2) - (x - 2)

= (x - 2).(x² - 1)

= (x - 2).(x - 1).(x + 1) 

a/ 5x²-5xy-3x+3y

=5x.(x-y)-3(x-y)

=(5x-3).(x-y)

b/ x³-2x²-x+2

=x².(x-2)-(x-2)

=(x²-1).(x-2)

=(x-1).(x+1).(x-2)